also what the rise per foot for a 1.5% grade is.[:|]
The “percent” grade is the rise per amount of horizontal run, thus a 1.5% grade is a means of expressing a 1.5" rise per 100" horizontal run (or a 1 mile rise per a 100 mile run, etc). Thus, a 1.5% grade rises .015 x 12" per foot, or 0.18"
A practical example…often we need to pass one track over another. The rise needed is (in HO) usually a 3" clearance over the lower track. If the upper track system has to be 3" clearance over the lower one, the track has to rise the clearance plus the subroadbed and roadbed (e.g., plywood and cork) height, let’s say 3-3/4" total. If you wanted to do that with a 1.5% grade, you would need a run of (3.75/1.5) x 100 = 250". Actually that would increase a bit because of smooth vertical transitions that need to occur at the bottom and top of the grade.
Note that in the grades we use of usually less than 3% or so, the distance of the slope is only a teeny bit more than the horizontal run, so if measuring a distance to get a given grade, either the horizontal or slope distances can be measured over a distance for essentially the same result. Your nominal 1.5% grade might be 1.48% or 1.52% or so but that won’t make a meaningful difference.
P.S. - we can help more if you tell us what you are trying to figure out.
LION got a 17% on an algebra final.
The issue is you have a track here ---->
and you want it to meet on the next level there ------->
You must simply connect the two and run the train. It it goes up then it is ok, if it does not go up, then you must move either here or there. Who cares what the finished grade is, LION graduated college Suma cum laude so maybe algebra in high school does not mean all that much.
ROAR