The calculator says that 80’ in “N” scale is 6". Let’s say you already know the “N” scale size of 6". How would you calculate what the real life size should be. I’ve tried, now I’m blue in the face & need help. Is there one of these calculators that will do it the one from the link above? Thanks in advance for any help & everyone have a safe happy holiday season.
N-scale is !/160th real size… That is 1 real foot equals 160 N-scale feet. So if say a boxcar is 4inches long ,divide 160n-scale feet by 4real inches, you get 40 N-scale feet.It will take 160,40 foot N-scale boxcars lined up to equal the length of one real 40 foot boxcar. Capeesh? BILL
This is why you should have paid attention to your math teachers back in Jr High or High school.
This is a simple fraction or ratio problem.
The dimension of the prototype will be called real size. The physical size of the scale model will be called the model size.
First all the units have to be in the same units, all in feet, all inches, all in meters, Doesn’t matter as long as the real and model size are in the same units.
To go from the real size to the model size, divide by scale ratio.
To go from the model size to the real size, multipy by the scale ratio.
The real car is 80 feet. The scale ratio is 160. 80/160 = .5. The model size is .5 FEET, which is 6 inches.
The model car is 6 inches. The scale ratio is 160. 6 x 160 = 960. The real size is 960 INCHES, which is 80 feet.
The model car is .5 feet. The scale ratio is 160. .5 x 160 = 80. The real size is 80 FEET.
There must be a lot of people like that because so many say N scale is half the size of HO scale. Since HO scale is 1/87.1, a scale half the size would have a ratio of 1/174.2. Since N scale is 1/160 (so they say), it is about nine percent larger than one-half of HO. … Or maybe there are just a lot of “big rounders” out there.